Hexcel IM7 carbon fiber
Transversely isotropic engineering approximation. Longitudinal strength and density are manufacturer values; transverse constants follow the cited micromechanics property table.
Tools for Research
Estimate direction-wise elastic constants, tensile and compressive strengths, density, thermal expansion and specific heat for a unidirectional fiber–matrix composite.
Infer missing isotropic constants from any valid pair of E, G, ν and K.
Use transparent Voigt, Reuss and mass-weighted mixture equations.
Create a CSV report and Abaqus engineering-constants material card.
Manufacturer and scientific-source presets; review applicability before use.
Transversely isotropic engineering approximation. Longitudinal strength and density are manufacturer values; transverse constants follow the cited micromechanics property table.
Results are up to date
The comparison chart and Abaqus export use the last calculated inputs.
E₁
139400.00 MPa
E1 = V_fE1_f + V_mE1_m
E₂
8554.73 MPa
1/E2 = V_f/E2_f + V_m/E2_m
E₃
8554.73 MPa
1/E3 = V_f/E3_f + V_m/E3_m
G₁₂
3176.29 MPa
1/G12 = V_f/G12_f + V_m/G12_m
G₁₃
3176.29 MPa
1/G13 = V_f/G13_f + V_m/G13_m
G₂₃
3176.29 MPa
1/G23 = V_f/G23_f + V_m/G23_m
ν₁₂
0.26
ν12 = V_fν12_f + V_mν12_m
ν₁₃
0.26
ν13 = V_fν13_f + V_mν13_m
ν₂₃
0.26
ν23 = V_fν23_f + V_mν23_m
ν₂₁
0.02
ν₂₁ = ν₁₂E₂/E₁
Xₜ — tension, direction 1
2128.00 MPa
direction-1 tensile yield/strength direct Rule of Mixtures
X꜀ — compression, direction 1
1128.00 MPa
direction-1 compressive yield/strength direct Rule of Mixtures
Yₜ — tension, direction 2
169.90 MPa
direction-2 tensile yield/strength inverse Rule of Mixtures
Y꜀ — compression, direction 2
272.73 MPa
direction-2 compressive yield/strength inverse Rule of Mixtures
Zₜ — tension, direction 3
169.90 MPa
direction-3 tensile yield/strength inverse Rule of Mixtures
Z꜀ — compression, direction 3
272.73 MPa
direction-3 compressive yield/strength inverse Rule of Mixtures
Composite density
1560.00 kg/m³
ρ_c = V_fρ_f + V_mρ_m
α₁
0.06 ×10⁻⁶/K
α1 = (V_fE1fα1f + V_mE1mα1m)/(V_fE1f + V_mE1m)
α₂
0.06 ×10⁻⁶/K
α2 = (V_fE2fα2f + V_mE2mα2m)/(V_fE2f + V_mE2m)
α₃
0.06 ×10⁻⁶/K
α3 = (V_fE3fα3f + V_mE3mα3m)/(V_fE3f + V_mE3m)
Specific heat cₚ
830.00 J/(kg·K)
c_p,c = w_fc_p,f + w_mc_p,m; w_i = V_iρ_i/ρ_c
Volumetric heat capacity
1294800.00 J/(m³·K)
C_v = ρ_cc_p,c